100x^2+120x+36=9

Solution for 100x^2+120x+36=9 equation:

100x^2+120x+36=9

We move all terms to the left:

100x^2+120x+36-(9)=0

We add all the numbers together, and all the variables

100x^2+120x+27=0

a = 100; b = 120; c = +27;
Δ = b2-4ac
Δ = 1202-4·100·27
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-60}{2*100}=\frac{-180}{200}
=-9/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+60}{2*100}=\frac{-60}{200}
=-3/10
$